SolutionT = 1/f therefore clock period = 1/(133 x 106) N = 266 000 CPU execution time for a program = NT = 266 000/(133 x 106) = 2 x 10-3 s = 2 milliseconds.
|
|
Cybercomputing - a web-based teaching aid.
SolutionT = 1/f therefore clock period = 1/(133 x 106) N = 266 000 CPU execution time for a program = NT = 266 000/(133 x 106) = 2 x 10-3 s = 2 milliseconds.
|
|
Cybercomputing - a web-based teaching aid.